Stream: Archive Mirror: Isabelle Users Mailing List

Topic: [isabelle] partial functions


view this post on Zulip Email Gateway (Aug 19 2022 at 13:32):

From: "Roger H." <s57076@hotmail.com>
Hi,

how can i prove

"the (f a) = b ⟶ ((f |` (- {a}))(a ↦ b)) = f"

Thank you!

view this post on Zulip Email Gateway (Aug 19 2022 at 13:33):

From: John Wickerson <johnwickerson@cantab.net>
I don't think you can. The fact that "the (f a)" is equal to "b" does not mean that "a" is in the domain of "f". Isabelle functions are always total, even "the". So the fact that "the (f a)" is equal to something doesn't actually tell you anything.

What you might have more luck with is this:

"f a = Some b ⟶ ((f |` (- {a}))(a ↦ b)) = f"

John

view this post on Zulip Email Gateway (Aug 19 2022 at 13:33):

From: "Roger H." <s57076@hotmail.com>
Hi,

thank you, but i dont know how to prove this either :-)
"f a = Some b ⟶ ((f |` (- {a}))(a ↦ b)) = f"Can you help me?

view this post on Zulip Email Gateway (Aug 19 2022 at 13:33):

From: "Roger H." <s57076@hotmail.com>
Nevermind
i used sledgehammer and got it.

Thank you anyway


Last updated: Nov 21 2024 at 12:39 UTC