Stream: Archive Mirror: Isabelle Users Mailing List

Topic: [isabelle] residual subgoals


view this post on Zulip Email Gateway (Aug 22 2022 at 12:45):

From: Buday Gergely <gbuday@karolyrobert.hu>
Hi,

following

http://stackoverflow.com/questions/35156803/sledgehammer-gives-insufficient-proof-tactic

I created

theory Even
imports Main

begin

inductive
structural_even :: "nat ⇒ bool"
where
"structural_even 0"
| "structural_even n ⟹ structural_even (Suc(Suc n))"

fun
computational_even :: "nat ⇒ bool"
where
"computational_even 0 = True"
| "computational_even (Suc 0) = False"
| "computational_even (Suc(Suc n)) = computational_even n"

lemma "computational_even n ⟹ structural_even n"
proof (induct n rule: computational_even.induct)
show "computational_even 0 ⟹ structural_even 0"
by (metis structural_even.intros(1))
next
show "computational_even (Suc 0) ⟹ structural_even (Suc 0)"
by (metis computational_even.simps(2))
next
show "⋀n. (computational_even n ⟹ structural_even n) ⟹ computational_even (Suc (Suc n)) ⟹ structural_even (Suc (Suc n))"
proof
fix n
assume "computational_even n ⟹ structural_even n"
from this show "computational_even (Suc (Suc n)) ⟹ structural_even n"
by (simp only: computational_even.simps(3))
qed
qed

end

view this post on Zulip Email Gateway (Aug 22 2022 at 12:45):

From: Lars Hupel <hupel@in.tum.de>
Hi Gergely,

Is it standard practice not to bother these but postpone solving them via the final qed?

I'd say it's not standard practice. Most Isabelle users prefer not using
meta-implications and meta-quantification in Isar proofs if it can be
avoided. See Lars Noschinski's answer here for a case where it actually
doesn't work if you use meta-implication:

<https://stackoverflow.com/a/25442787/4776939>

Isabelle2016 has changed some things with that respect. For example, you
can now write

fix P
assume "P x" for x

instead of

fix P
assume "⋀x. P x"

Cheers
Lars

view this post on Zulip Email Gateway (Aug 22 2022 at 12:46):

From: Buday Gergely <gbuday@karolyrobert.hu>
Hi Lars,

Thanks. Re-formulating my goal I wrote

lemma
fixes n :: "nat"
assumes "computational_even n"
shows "structural_even n"
proof (induct n rule:computational_even.induct)

which results in

goal (3 subgoals):

  1. structural_even 0
  2. structural_even (Suc 0)
  3. ⋀n. structural_even n ⟹ structural_even (Suc (Suc n))

where the 2nd subgoal is simply not true.

What is wrong with that lemma expression?

view this post on Zulip Email Gateway (Aug 22 2022 at 12:46):

From: Johannes Hölzl <hoelzl@in.tum.de>
Am Mittwoch, den 03.02.2016, 11:50 +0100 schrieb Buday Gergely:

Hi Lars,

Is it standard practice not to bother these but postpone solving
them via
the final qed?

I'd say it's not standard practice. Most Isabelle users prefer not
using meta-
implications and meta-quantification in Isar proofs if it can be
avoided. See
Lars Noschinski's answer here for a case where it actually doesn't
work if you
use meta-implication:

<https://stackoverflow.com/a/25442787/4776939>

Thanks. Re-formulating my goal I wrote

lemma
fixes n :: "nat"
assumes "computational_even n"
shows "structural_even n"
proof (induct n rule:computational_even.induct)

You need to add the assumption with "using":

assumes "computational_even n"
shows "structural_even n"

using assms
proof (induct n rule:computational_even.induct)

Then your 2. goal should state:

computational_even (Suc 0) ==> structural_even (Suc 0)

Which is true as "computational_even (Suc 0) = False"

which results in

goal (3 subgoals):
1. structural_even 0
2. structural_even (Suc 0)
3. ⋀n. structural_even n ⟹ structural_even (Suc (Suc n))

where the 2nd subgoal is simply not true.

What is wrong with that lemma expression?

view this post on Zulip Email Gateway (Aug 22 2022 at 12:46):

From: Manuel Eberl <eberlm@in.tum.de>
You are not using your assumption at all, so effectively, you're trying
to show that /every/ number n is structurally even, which is, of course,
false.

Chain in the assumption by putting a "using assms" in front of your
"proof". Then you will have the additional assumption
"computational_even (Suc 0)" in the second case, and that should be
false, which means the second case is trivially provable.

Cheers,

Manuel

view this post on Zulip Email Gateway (Aug 22 2022 at 12:46):

From: Tobias Nipkow <nipkow@in.tum.de>
You need not modify the lemma statement and "proof" line at all. Induction is
very happy with implicational goals.

Tobias
smime.p7s


Last updated: Nov 21 2024 at 12:39 UTC