Stream: Archive Mirror: Isabelle Users Mailing List

Topic: [isabelle] Isabelle


view this post on Zulip Email Gateway (Aug 18 2022 at 11:45):

From: chouaffe frannck-edmond <chouaffe2000@yahoo.fr>
Hello isabelle users,
I just want to ask if I can use a Mathml file as an input format for isabelle. I have written some mathematical proofs in Mathml, and I would like to check it within isabelle. Is it possible?

Kind regards.

Edmond


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view this post on Zulip Email Gateway (Aug 19 2022 at 15:59):

From: mahmoud abdelazim <m.abdelazim@icloud.com>
i am user of Isabelle and i am trying to proof a theorem for example :

theorem rev_rev [simp]: "rev(rev xs) = xs"
apply(induct_tac xs)
apply(auto)
done

The steps of auto could be done using separate steps?
The steps of induct_tac could be done using separate steps?
please provide an example

view this post on Zulip Email Gateway (Aug 19 2022 at 15:59):

From: Lawrence Paulson <lp15@cam.ac.uk>
Induction cannot be broken down into smaller steps. It is a primitive concept.
Larry Paulson

view this post on Zulip Email Gateway (Aug 19 2022 at 15:59):

From: Alfio Martini <alfio.martini@acm.org>
Hi Mahmoud,

Yes, you can prove this theorem in a lot of detail using the proof language
Isar (see the
tutorial "Programming and Proving in Isabelle/HOL").

As an example, I attach a theory that shows the proof of one of the lemmas
you need to prove your theorem.
I use one of the several possible styles.

Best!
isarlistexample.thy

view this post on Zulip Email Gateway (Aug 19 2022 at 16:21):

From: Andrew Boyton <Andrew.Boyton@nicta.com.au>
Hi

Auto runs on both subgoals. Tracing what auto does for each shows auto used the following rules.

  1. rev (rev []) = []
    simp_thms(6): (?x = ?x) = True
    rev.simps(1): rev [] = []

  2. ⋀a list. rev (rev list) = list ⟹ rev (rev (a # list)) = a # list
    True_implies_equals: (True ⟹ PROP ?P) ≡ PROP ?P
    simp_thms(6): (?x = ?x) = True
    append_Cons: (?x # ?xs) @ ?ys = ?x # ?xs @ ?ys
    append_Nil: [] @ ?ys = ?ys
    rev.simps(1): rev [] = []
    rev.simps(2): rev (?x # ?xs) = rev ?xs @ [?x]
    rev_append: rev (?xs @ ?ys) = rev ?ys @ rev ?xs
    rev_rev_ident: rev (rev ?xs) = ?xs

Andrew


Last updated: Nov 21 2024 at 12:39 UTC